Unformatted text preview: C. 5 m/s Faraday’s Law: D. 6 m/s E. 9 m/s dΦ
dΦ
E d = −
⇒ ε = IR =
∫
dt
dt As the moving conductor slides downward the area of the loop, and therefore the flux, increases. v = 6 m/s IR = dΦ
dA
dH
=B
= BL
= BLv
dt
dt
dt v= IR 3.75 A ⋅ 20 Ω
=
= 6 m/s
BL
5T ⋅ 2.5 m Physics 212 Lecture 29, Slide 13 Phasor diagram at t = 0 Phasers
What is VC at t = π/(2ω)
(A) α + VC max sin α (C) + VC max cos α (B) − VC max sin α (D) − VC max cos α Phasor diagram at t = π/(2ω)
VR α VC VL Voltage is equal to projection of phasor along vertical axis
Physics 212 Lecture 29, Slide 14 Ampere’s Law Integrals
. Two infinitely long wires carrying current run into the page as indicated. Consider a closed
triangular path that runs from point 1 to point 2 to point 3 and back to point 1 as shown.
Which of the following plots best shows B·dl as a function of position along the closed path? B B The magnetic field points in the azimuthal direction and is oriented clockwise.
No current is contained within the loop 1231, therefore NOT (A)
The magnetic field falls off like 1/r (r is the distance from the wire).
From 3 to 1, B∙ dl is < 0 , la rg e s t m a g...
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 Fall '08
 Kim
 Physics, Electrostatics, Electric charge

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