This preview shows page 1. Sign up to view the full content.
Unformatted text preview: variances
variances
The MS(B) and MS(W) are two sample
The
variances and that’s what we divide to find F.
variances
F = MS(B) / MS(W) For our data, F = 951.0 / 161.2 = 5.9 31 OneWay ANOVA
OneWay Adding F to the table … Source SS df MS Between 1902 2 951.0 Within 3386 21 161.2 Total 5288 23 F p 229.9 5.9 32 OneWay ANOVA
OneWay The F test is a right tail test
The F test statistic has an F distribution
The
with df(B) numerator df and df(W)
denominator df
denominator
The pvalue is the area to the right of the
The
test statistic
test
P(F2,21 > 5.9) = 0.009 33 OneWay ANOVA
OneWay Completing the table with the pvalue Source SS df MS Between 1902 2 951.0 Within 3386 21 161.2 Total 5288 23 F p 229.9 5.9 0.009 34 OneWay ANOVA
OneWay The pvalue is 0.009, which is less than
The
the significance level of 0.05, so we reject
the null hypothesis.
the
The null hypothesis is that the means of
The
the three rows in class were the same, but
we reject that, so at least one row has a
different mean.
different 35 OneWay ANOVA
OneWay There...
View
Full
Document
This note was uploaded on 02/25/2013 for the course STATS 104 taught by Professor Mrs during the Spring '13 term at Lahore University of Management Sciences.
 Spring '13
 mrs
 Variance

Click to edit the document details