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hwksol09 - Racks/s 04C SITC€ T5 5 = V 50x A Inf-’-...

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Unformatted text preview: Racks/s 04C SITC€ T5 5 = V 50x A Inf-’- JZ—(d "957‘ =1ziffirgzflfla?‘ = $4? KM 43“ 5%716097’ x = I ZSOTI pxldx 200 Ixx== 1750’“? J Xidx : M "H o '3’ ‘0 m : owfn‘ézd“ " P“ (“D/(0200de = (057T ' (r haméz ) 4% 31% 31W 4—”; = S7\73§IYm/\ [M P:?5/@’ ) FOR A DISC: 16;: 3ier Outer rfi%: Ién = LZEP(l)TY[2\‘SY](2~§)7‘~§[P(|)1T/Z)Zj(2)z= llsfiwp inner my 16/; = ‘if P(D%§)'W('Z)L]C7«)Z~ iiflwzfinflfjflf = (-87“; T30 16: f— Im+ 1&2: I3~4—0§TT TbTbl' MASS : m = ff’fi(z\‘§)z—Tr[z)lj(( )+{>[rr(z)z -Tv [I)Z](o\2§) c an? '10 I 1'61 +m (2&1: flpfla~403+ 303?]:32'1357? p: FIG/(32g) /~ IO=C32JSSX670TFW3LZ =v2€§2=§5 swaxgz '7/50 16' 15 not needei becewse (i=0 :7._ —=; _ ’~P+F;CA+E51_ flax]. PEAS/“AU _m _ _, m T 4, hj‘beMUYn P) 88:0) A ' 4% Sfaffwlly/ z m #6152: [—(I~9)(80)+P(4)J ,~ 9:30 >— , mar FfA=QT3XQO>=Z4 /‘ P=307Z¢P ’9 lel Maw 7”“ 795% w~fi ' / " ’ A t 1 kmfl/«Zfiaéfim: m061X5-P+(0‘a{@) Ba 2MA8=1ADZ+?6AYM%I ) ol=0 —(.‘<>(s~o>+?(4)=oflfipmrgx}[5§]x[“"+(81y80)) 0 0 0 0 —120-+4P: .2\9‘(—P+/b) ; L99ng ; p: 531§5% 11ng 63/ “6.5 ‘33 3CCflf60+Tbmof mI Mmz 9(7: 04 MTaqra = m, aé‘a + mlaéfla 0‘75 W51" -=‘7o(o)+ no £13 £6 [35 THE 6604 LS MOUONLESS, THE POOL moves upwarzo Prr mag :05. ’2 F3: A 3 +%~@20 +76)LQ\80= {7,0 (t a, 2 F375 2 b j + ail/15% ma-Zéfl + Pal/3x "(‘23—‘22 )J’Z‘g - A {a (as) + (0\7)(no)(4~8')+(0~'SX70)(9~8'O= O ’0‘7(70)[0)"0'7(|20)6(a_ swam: 11574 + 24 a6 = lax/X3 0r A35 =%3~92+ W243 R‘elfiv'frémfwnfi -; ix; 2 J/‘Or ZWMS (100 2 9 33m +672 a5 ; a6 é— 3% M/sa?‘ 8%: I20 615 + \864 ~A3 =IZOZIU+1864-ODSQ «672626, = 152%, + @308 ; 'sz 9% s 2(600) /- aa $94 ChUDfie vblue 2 é; 51 egg—CL NA NB [oszwazNe 1 BOOVfl 5‘60”): 336:1? =3 “ ‘“NAO~ZS)+NB(0~7S)-(oszA+0\2NB)(o~5/§:0 CASE :— Ree/r.th Qrwe : LeiJC oak/Mo ) ho‘fe: NAi—O, 5—0:“): *1 \ngA + M3078 - 0«Z(0~Z‘3‘)) :O Na: (MS/m) NA : L838 NA var COMP: NA +Ms = NA (:+l~83&>= 1476 NA = 935 /‘ NB=9930) )(—-Cem : ‘_ 019930 _ * (m P 016, ~fi¥ « t~z7l m ~ U, 30 2222'“ Uzak ; tzg—Z :‘7‘4—84&1 5 ~ Comp z Np,(-l\LS‘—{0~L)(0\$S3)+N8(0*7'3-—0~2 (basil-=0 l~32NA=o~bS Ne. ) Ne: M44 NA ‘6-Cova: NA+Ng= MA(i+I\Q4I)=|47I5‘ NAZSQOB ) NB=47I2 X‘CO'WP: a&:.0‘1(52‘;360iu7’2 : [‘962 43—222 1%: 2,3,3: --= (133% '7 5 9 :tam-l (0413/06) 1—2262?) _ ~3_ —wan22\bz° MU mgé ‘ O 'i T w;2g920-(20)(9~8/)-30a0~2/\)1 X—cépmg : M : T %-wmp: 1226\2 'T': . M: (02»8! ; IA :[2O)[0\000"‘=0\162 A 5 {2/15. = l 2 30M ._.(goXOq7/9)+(0\2)(102L80(0‘ll§)5 we 20< 046.2% 04 = ‘7»282 “6ch g x m cw, W6? Gwaw M amt; shfm 4mm F; =fl5N=0~3(Ioo)—:30 D Fwwns NOTTDNRSS Me 3009‘s) loac i 3006;) 2 7t é. IS Seast For 2e 718 See J m: lO/t -—[(0~2)(too)](0\s)=zor~(0 T <—-’“—"’— rgdze = IQwL o ; 15,: LZG‘Z’aXo‘s-Y: 003% N=Ioo [511407055 =f(20-u~25)*10(o®)3= 37: LJ’ v= 3‘7S/o~03&&= Qé‘éS “4&1 —-—-‘7/' '0 OLA = $8 = 4 /~ Tm = (60Y0‘4)2:9~é; 3610440106571= 4.6; I06 = £56 + (W) (08):: 2414 TM; 100 =Iem+ (40) (0‘97 : 14‘6' m9 620 N If is no‘t 30d {’0 Uje, ‘H'ejcorCe 260511?“ 9;" D becévs-c ‘H1e ferces We uh known. 30" w, C: Z’Mo: '(I)TA3+(O\S)(60)(Q~€I)MA 50" = 100% "TAB + l47‘ IS‘ 2 2+,“ D = Z Mo = +0) TAB +(0«s)(40)(41~‘&1)m30’ : 100% TAB + 98'! = MUM App: 24923::‘59-50L ,— oz =é\2l “d/se: ...
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This homework help was uploaded on 02/06/2008 for the course CE 325 taught by Professor Docwong during the Spring '08 term at USC.

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hwksol09 - Racks/s 04C SITC€ T5 5 = V 50x A Inf-’-...

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