Unit_5A_Activity_Equation_of_a_Parabola_Based_on_Its_Focus_and_Directrix_CA

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Course ActivityEquation of a Parabola Based on Its Focus andDirectrixThe Lesson Activities will help you meet these educational goals:Content Knowledge—You will derive the equation of a parabola given a focus anddirectrix.Mathematical Practices—You will make sense of problems and solve them.DirectionsPleasesave this documentbefore you begin working on the assignment. Type youranswers directly in the document._________________________________________________________________________Teacher-Graded ActivitiesWrite a response for each of the following activities. Check the Evaluation section at the endof this document to make sure you have met the expected criteria for the assignment. Whenyou have finished, submit your work to your teacher.1. Deriving the Equation of a Parabola Given a Focus and Directrix1( )y x h k= − +4pa. The vertex form of the equation of a verticalparabolais given bywhere (h,k) is the vertex of the parabola and the absolute value ofpis the distancefrom the vertex to the focus, which is also the distance from the vertex to thedirectrix. You will use the GeoGebra geometry tool to create a vertical parabola andwrite thevertex form of its equation. OpenGeoGebra, and complete each stepbelow. If youneed help, follow theseinstructionsfor using GeoGebra.i. Mark the focus of the parabola you are going to create atF(6, 4). Draw a horizontalline that is 6 units below the focus. This line will be the directrix of your parabola.What is the equation of the line?2,

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Term
Spring
Professor
FairbairnDonaldM.
Tags
Conic section

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