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Solutions to Homework Assignment 1_2

For column 2 to be a pivot column 4h 8 must not be

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Unformatted text preview: o be a pivot column, –4h + 8 must not be zero. This happens when h 2. (k can be anything) c. Many Solutions: In order to have many solutions, we must have a consistent system with at least one free variable. This means that the last row must be a row of all zeros. This happens when h = 2 and k = 8. 21. Discussed in class… a. False b. False c. True d. True e. False...
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