Component c6h6 c6h5cl c6h4cl2 c6h3cl3 wt frac 065

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Unformatted text preview: ponent C6H6 C6H5Cl C6H4Cl2 C6H3Cl3 Wt. Frac. 0.65 0.320 0.025 0.005 Wt in 100 gm 65 32 2.5 0.5 Moles 0.833 0.284 0.0170 0.00275 Mole Fraction 0.732 0.250 0.0149 0.00242 In order to calculate the excess we need to know what basis to use. Since monochlorobenzene is the desired product let’s assume that the appropriate ratio of chlorine to benzene is set by the stoichiometry of the reaction C6 H 6 Cl 2 C6 H 5 Cl HCl Thus a ratio of 1.0 mole Cl2 to 1.0 mole C6H6 would be a stoichiometric ratio. To determine the numbers asked in part (a) we would take a basis for the product stream (say 100 moles of product gas). Using the stoichiometry this could be converted back to moles of C6H6 and Cl2 as reactants. To do this we would also need the stoichiometry of the side reactions which are: C 6 H 5 Cl Cl 2 C 6 H 4 Cl 2 HCl C 6 H 4 Cl 2 Cl 2 C 6 H 3 Cl 3 HCl The last part of (a) requires a conversion back to mass units. To do this we would again need average molecular weights. But this is available for all...
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This note was uploaded on 03/01/2013 for the course CHEME 2171 taught by Professor Benton during the Spring '12 term at LSU.

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