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Soln01 - Homework#1Solution EMSE426,Spring2010 Q1...

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Homework #1 Solution EMSE 426, Spring 2010 Q1 a) : http://cst‐www.nrl.navy.mil/lattice/struk/c4.html (image from ) b) I (bcc) atoms (6 O; 2 Si) c) 8 Q2: Homoepitaxy: Eptitaxy on the same material. Heteroepitaxy: Epitaxy on different materials. Homoeptitaxy is often used to grow film with higher purity than the substrate or to grow films with different doping concentration. Heteroepitaxy is used to help growing a single crystal film from materials that lly doesn’t easily achieve single crystal. usua Q3: a) The atomic volume is Ω = a3 /n ν c = 2.00 × 10 −29 m 3 ; density ρ = W/V = 2.33×10 3 kg/m 3 . b) Surface density NS,(100) = 2/a 2 = 6.78×10 14 atoms/cm 2 , N S,(110) = 4/√2a 2 = 9.60×10 14 atoms/cm 2 , and N S,(111) = 4/√3a 2 = 7.83×10 14 atoms/cm 2 . d) Height of a monolayer h(100) = a/4, h(110) = √2a/4, and h(111) = √3a/12 or √3a/4. Hint: Consider (111) planes like x + y + z = 1, x + y + z = 3/4 + 1/4 + 3/4 =
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Soln01 - Homework#1Solution EMSE426,Spring2010 Q1...

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