MAT-121: COLLEGE ALGEBRA
Written Assignment 2
2.5 points each
SECTION 2.1
Algebraic
For the following exercise, solve the equation for
y
in terms of
x
1.
8
x
+
3
y
=
11
3
y
=−
8
x
+
11
y
=
−
8
x
+
11
3
For the following exercise, find the distance between the two points. Simplify your answer, and write the
exact answer in simplest radical form for an irrational answer.
2.
(
0,
−
5
)
and
(
7,4
)
√
(
7
−
0
)
2
+
[
4
−(−
5
)
]
2
√
(
7
)
2
+
(
9
)
2
√
49
+
81
√
130
Graphical
For exercises
3 and 4
, plot the three points on the given coordinate plane. State whether the three points
you plotted appear to be collinear (on the same line).
3.
(
10,4
)
,
(
−
4,
−
2
)
,
(
3,2
)
(Use a scale of 2 for each axis.)
The three points are noncollinear.
.
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4.
Name the quadrant in which the following points would be located. If the point is on an axis, name
the axis.

Numeric
For the following exercise, find and plot the
x
- and
y
-intercepts, and graph the straight line based on those
two points.
5.
−
2
x
+
6
y
=
18
−
2
x
+
6
(
0
)
=
18
−
2
x
=
18
x
=−
9
(-9,0)
−
2
(
0
)
+
6
y
=
18
6
y
=
18
y
=
3
(0,3)
For the following exercise, use the graph to
the right.
6.
Find the distance between the two
endpoints using the distance
formula. Round to three decimal
places.
(Use a scale of 1 for each axis.)
Copyright © 2019 by Thomas Edison State University. All rights reserved.

7.
A woman drove 15 miles directly east from her home, made a right turn at an intersection, and
then traveled 8 miles south to her business. If a road was made directly from her home to her
business, what would its distance be to the nearest tenth of a mile?

Copyright © 2019 by Thomas Edison State University. All rights reserved.

SECTION 2.2
Algebraic
For the following exercise, solve the equation for
x
.
8.
3
x
2
+
2
5
=
7
x
10
−
3
4
20
(
3
x
2
+
2
5
)
=
(
7
x
10
−
3
4
)
20
30
x
+
8
=
14
x
−
15
16
x
=−
23
x
=
−
23
16
For the following exercise, solve each rational equation for
x
. State all
x
-values that are excluded from the
solution set.
9.
4
+
5
2
x
−
7
=
x
−
4
2
x
−
7
2
x
−
7
(
4
+
5
2
x
−
7
)
=
(
x
−
4
2
x
−
7
)
2
x
−
7
8
x
−
28
+
5
=
x
−
4
8
x
−
23
=
x
−
4
7
x
=
19
x
=
19
7
For exercises
10 and 11
, find the equation of the line using the point-slope formula. Write all the final
equations using the slope-intercept form.
10.
(
3,0
)
with a slope of
3
2
y
−
0
=
3
2
(
x
−
3
)
y
=
3
(
x
−
3
)
2
11.
Perpendicular to
5
y
=
2
x
−
6
and passes through the point (-1, 5)
5
y
=
2
x
−
6
y
−
5
=
2
5
[
x
−(−
1
)
]
y
=
2
5
x
−
6
y
−
5
=
2
5
x
+
1
Copyright © 2019 by Thomas Edison State University. All rights reserved.