Lecture 5b Hardy W - frequencies from genotype frequencies...

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Hardy-Weinberg Part II
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Determining heterozygotes in a population, assuming H-W equilibrium
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What you know Pop = 100 Black corn: dominant : 36 ind. Yellow corn: recessive : 64 ind. Assuming H-W equilibrium, what is the freq. of heterozygote individuals?
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Solution q 2 = 64/100 (.64) q = 0.8 p = 0.2 2pq = 0.32
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Ex 4) Is a population in equilibrium?
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Question: Do freq. in MN blood group in Eskimo populations conform to HW model? MN blood group co-dominant alleles (M, N) Freq. of each genotype are KNOWN
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Observed Genotype frequencies Observed Genotype FREQUENCIES 0.835 MM 0.156 MN 0.009 NN Observed allele freq. M alleles (p) = ? N alleles (q) = ?
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Solution M alleles (p) = 0.835 + 1/2(0.156) = 0.913 N alleles (q) = 0.009 + 1/2(0.156) = 0.087 Please note the difference from the previous examples (in “Lecture 4b Allele frequencies”) In this example, you are calculating allele
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Unformatted text preview: frequencies from genotype frequencies instead of from numbers of individuals with a particular genotype. • See EXCEL spreadsheet Expected Genotype freq. • M allele (p) = 0.913 • N allele (q) = 0.087 • Calculate Expected Genotype Frequencies • p 2 = MM 0.834 • 2pq = MN 0.159 • q 2 = NN 0.008 Compare Observed and Expected • Obs. Genotype Exp. Genotype • MM 0.835 0.834 • MN 0.156 0.159 • NN 0.009 0.008 Conclusion • MN blood group is in H-W equilibrium • Not affected by evolutionary mechanisms • Humans do not choose mates based on MN genotype Steps • 1. Estimate genotype freq. by observation (given) • 2. Calculate obs. allele freq. from obs. genotype freq. • 3. Use obs. allele freq. to calculate exp. genotypes according to H-W. principle • 4. Compare obs. and exp. values • 5. Suggest whether data support the null hypothesis...
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This note was uploaded on 04/07/2008 for the course BIO 124 taught by Professor Griscom during the Fall '07 term at James Madison University.

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Lecture 5b Hardy W - frequencies from genotype frequencies...

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