Unit 4 Congruency_solutions-1 (1) - Unit 4 Congruency Fill in the blanks to complete the following proofs logically 1 I ABCD in lie \u00b5 i on is a the

# Unit 4 Congruency_solutions-1 (1) - Unit 4 Congruency...

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Unit 4- Congruency Unit 4- content adapted from Deerfield Academy and Penner 1 Fill in the blanks to complete the following proofs logically: 1. 2. I in ABCD is a rhombus µ lie on the PBofAC i E AE EE PE EB SSS HIT EF JE EG HET FEG j l SAS HEJ It FEG CPCTC
B THE D D C DA ODED BOC by SAS 2 sides and the included vertical K's therefore by CPC TC AD BC ow focus on AB's DC A OBE L DOC by vertical S 23 24 and Ct EL 2 since they are base Is of isosceles triangles since mL3tmL4 t m L Z 180 and m L l 1mL 2 tm CZ so So a mL3tmL4tmLZ mcltm Z ABI DI mum Esp by subtraction 2mL 3 2 m Ll or m L3 MC 1 So m L 4 m C 2 by substitution All 1
i ABECISDCB Sss 2B ELC CRTC AT EAT if then SABC is isosceles Def of qi SABCESDCB A AS ATTEDT CP CTC
statementsReasoni ATE AT BDC Ecce B Glen 8 E 8I 7 SDBCESECB AAS CDIBE CPCTC d r z L Since ABCD is a square AI E BT and LA E LB since AM NB and Art and MBT both share MN AN EBT Through SAS S AND E D BMC and Li EL 2 by CP CTC Therefore MIENT since then
A is peasors statements o.si E.I T i Iii AFTAB Reflexive SABCES BAD HL ATE BT CRTC
B SABCES BCD by SAS A q c 4 s 5 and sides 5 by µ given is AT FBI 6pct 1 72 CPCTC so I BPC is isosceles BFI PT if then Time Bae.EE maIssi5esaeaEdb s A D SAS Therefore AT BB by CRTC F L CBD and L ACB are also corresponding parts and therefore E BTEPT since Dc then D BPC is therefore isosceles
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