2_Physics Homework - Chapter 4

2_Physics Homework - Chapter 4 - y-component of the pull F1...

Info icon This preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
y-component of the pull F 1 is F 1y =F 1 sin31° =(985 N)(0.5150) = x-component of the pull F 2 is F 2x = -F 2 sin32° =-(788 N)(0.5299) = Here the negative sign shows that the x-component of the pull F 2 is in the negative x direction y-component of the pull F 2 is F 2y =F 2 cos32° =-(788 N)(0.8480) = x-component of the pull F 3 is F 3x = -F 3 cos53° =-(411 N)(0.6018) = Here the negative sign shows that the x-component of the pull F 3 is in the negative x direction y-component of the pull F 3 is F 3y = -F 3 sin53° =-(411 N)(0.7986) = Here the negative sign shows that the y-component of the pull F 3 is in the negative y direction. (b) Let F be the resultant of the three pulls. Then the x- component of the F is given by And the y-component of F is given by Hence the net magnitude of the resultant force of the three pulls is: And the direction of the resultant force can be calculated as: EX 4.7 A 68.5-kg skater moving initially at 2.40 m/s on rough horizontal ice comes to rest uniformly in 3.52s due to friction from the ice. What force does the friction exert on the skater?
Image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 2
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern