4_Physics Homework - Chapter 6

4_Physics Homework - Chapter 6 - Using(4 and(2(ii Net force...

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Using (4) and (2) This implies tension (ii) Net force acting on smaller block is Work done on the smaller block is (c) total work done on the system is Now work done on the smaller block from gravity is calculated as Both are same (d) Given: Initial velocity m/s Distance m The acceleration of the smaller block is Using the kinematic relation the speed of the block can be calculated as: EX 6.23 A sled with mass 8.00 kg moves in a straight line on a frictionless horizontal surface. At one point in its path, its speed is 4.00m/s after it has traveled 2.50 m beyond this point, its speed is 6.00m/s Use the work energy theorem to find the force acting on the sled, assuming that this force is constant and that it acts in the direction of the sled’s motion. Mass of sled Initial speed Final speed Displacement Force According to the work energy theorem we have But we knot that work done by a body is Substituting all the given values we get EX 6.37 A 6.0-kg box moving at 3.0 m/s on a horizontal, frictionless surface runs into a light spring of force constant 75 N/cm.
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