Set probability problems

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Unformatted text preview: ∩ B) (3) [2] [1] A − (A − B) = A ∩ (A ∩ Bc )c = A ∩ (Ac ∪ B) (10) (7,5) e b¡ b fcdc¡ R Q49E4 H F E SaPIGaD )0 [.] )0 )0 Y `A )0 )0 )0 W T¡ T XUVU¡ )0 )0 )0 )0 )0 )0 )0 )0 )0 )0 )0 )0 )0 )0 )0 )0 )0 )0 )0 )0 )0 )0 )0 )0 )0 )0 R Q49E4 H F E SB@PIG@D )0 )0 )0 )0 )0 )0 )0 )0 )0 C 4 ( B@787531 A 49 46 4 2 )0 )0 )0 )0 )0 )0 )0 )0 )0 )0 )0 )0 )0 )0 )0 )0 )0 )0 )0 )0 )0 )0 )0 )0 )0 )0 )0 )0 )0 )0 )0 )0 )0 )0 )0 A )0 (.) B Ac )0 22: )0 11: )0 )0 ¡( ¡' A • • C A • B C B †6: %# ! &$" ¨¦¤¢ §  §   © § ¥ £ ¡ Cp‡… a‡y{aD †@PgBaBIF 4 w D… ’ Q 4 H s 4 9 E6 4 9 4 H r ¡ te Y A s PI&… @tyza9 6 E C 4 w D… ’ Q 4 W r W ~} d| ¡ ¡ ¡ 6PE 4 wu1 6 E C 4 w D… ’ Q 4 Px&… @ty{@9 ¡¡ r W...
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This note was uploaded on 03/20/2013 for the course MATH UA 125 taught by Professor Shatah during the Spring '10 term at NYU.

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