IOE366W13-Exam2-practice-sol

# Answer where s are independent and normally

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Unformatted text preview: d normally distributed, each with mean 0 and variance (b) Obtain the ANOVA table Source df SS MS A 2 11,573.38 5786.69 B 4 17,930.09 4482.52 AB 8 1734.17 216.77 Error Total 30 44 4716.67 35,954.31 f MSA/MSE = 36.81 MSB/MSE = 28.51 MSAB/MSE = 1.38 157.22 and then test at the 0.01 significance (c) State null and alternative hypotheses, level. Answer) for all at least one Test statistic, Critical value, At significance level .01, we fail to reject the null hypothesis because we conclude that there is no interaction between the two factors. (cf. Example 11.7) 6 of 7 . Therefore, IOE 366 Fall 2012 Practice and then test at the 0.01 significance level. (d) State null and alternative hypotheses, Answer) at least one Test statistic, Critical value, At significance level .01, the null hypothesis is rejected because conclude that the main...
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## This note was uploaded on 04/04/2013 for the course IOE 366 taught by Professor Game during the Winter '08 term at University of Michigan.

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