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Unformatted text preview: d normally distributed, each with mean 0 and variance (b) Obtain the ANOVA table
Source df SS MS A 2 11,573.38 5786.69 B 4 17,930.09 4482.52 AB 8 1734.17 216.77 Error
= 1.38 157.22 and then test at the 0.01 significance (c) State null and alternative hypotheses,
at least one Test statistic,
At significance level .01, we fail to reject the null hypothesis because
we conclude that there is no interaction between the two factors.
(cf. Example 11.7) 6 of 7 . Therefore, IOE 366 Fall 2012
Practice and then test at the 0.01 significance level. (d) State null and alternative hypotheses,
Answer) at least one
At significance level .01, the null hypothesis is rejected because
conclude that the main...
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This note was uploaded on 04/04/2013 for the course IOE 366 taught by Professor Game during the Winter '08 term at University of Michigan.
- Winter '08