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IOE366W13-Exam2-practice-sol

IOE366W13-Exam2-practice-sol - IOE 366 Fall 2012 Practice...

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IOE 366 Fall 2012 Practice 1 of 7 Part 1. Multiple Choice and Fill-in the Blanks 1 . In a single-factor ANOVA problem involving five populations or treatments, which of the following statements is true about the alternative hypothesis? A. All five treatment means are equal. B. All five treatment means are different. C. At least two of the treatment means are different. D. At least three of the treatment means are different. E. At most, two of the treatment means are equal. ANSWER: C 2. In a single-factor ANOVA problem involving four populations or treatments, the four sample standard deviations are 25.6, 30.4, 28.7, and 32.50. Then, the mean square for error (MSE) is 3. In a single-factor ANOVA problem involving 3 treatments, the treatment means were 5, 6, and 9. If each observation in the third treatment was increased by 20, the test statistic value f would Answer : A ̅ is increased by 20 while ̅ is only increased by , leading to increased MSTr ( i.e ., enlarged between-samples variation). At the same time, MSE remains the same. As a result, increases. ( cf. p . 394-395) 4. For a multiple regression model, 2 ( ) 250 i y y and 2 ˆ ( ) 60 i i y y , what is the proportion of the total variation in the observed i y ‟s that is explained by the regression model is
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IOE 366 Fall 2012 Practice 2 of 7 5. In the two-factor ANOVA model with interaction, assume that there are 3 levels of factor A, 2 levels of factor B, and 3 observations for each of the six combinations of levels of the two factors. Then the critical value for testing the null hypothesis of no interaction between the levels of the two factors at the 0.05 significance level is
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