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MULTIPLE CHOICE.
Choose the one alternative that best completes the statement or answers the question.
Determine whether the given procedure results in a binomial distribution. If not, state the reason why.
1) Spinning a roulette wheel 6 times, keeping track of the occurrences of a winning number of "16".
1)
A) Procedure results in a binomial distribution.
.
B) Not binomial: there are more than two outcomes for each trial.
C) Not binomial: the trials are not independent.
D) Not binomial: there are too many trials.
Solve the problem.
2) On a multiple choice test with 18 questions, each question has four possible answers, one of which
is correct. For students who guess at all answers, find the variance for the number of correct
answers.
2)
A) 33.8
B) 11.4
C) 1.8
D) 3.4
Find the indicated mean.
3) A certain rare form of cancer occurs in 32 children in a million, so its probability is 0.000032.
In the
city of Normalville there are 76,430,000 children. A Poisson distribution will be used to
approximate the probability that the number of cases of the disease in Normalville children is more
than 2. Find the mean of the appropriate Poisson distribution (the mean number of cases in groups
of 76,430,000 children).
3)
A) 245
B) 2450
C) 24,500
D) 0.000032
Find the indicated z score. The graph depicts the standard normal distribution with mean 0 and standard deviation 1.
4)
Shaded area is 0.0694.
4)
A) 1.45
B) 1.39
C) 1.26
D) 1.48
Solve the problem. Round to the nearest tenth unless indicated otherwise.
5) The serum cholesterol levels for men in one age group are normally distributed with a mean of
178.3 and a standard deviation of 40.4. All units are in mg/100 mL. Find the two levels that separate
the top 9% and the bottom 9%.
5)
A) 124.2 mg/100mL and 232.4 mg/100mL
B) 108.0 mg/100mL and 248.6 mg/100mL
C) 165.4 mg/100mL and 191.23 mg/100mL
D) 161.7 mg/100mL and 194.9 mg/100mL
Solve the problem.
6) Human body temperatures are normally distributed with a mean of 98.20°F and a standard
deviation of 0.62°F. If 19 people are randomly selected, find the probability that their mean body
temperature will be less than 98.50°F.
6)
A) 0.4826
B) 0.3343
C) 0.0833
D) 0.9826
1

Find the indicated critical z value.
7) Find the critical value z
΅
/2
that corresponds to a 98% confidence level.
7)
A) 1.75
B) 2.575
C) 2.33
D) 2.05
Do one of the following, as appropriate:
(a)
Find the critical value z
΅
/2
, (b) find the critical value t
΅
/2
, (c) state that
neither the normal nor the t distribution applies.
8) 95%; n
=
11;
Η
is known; population appears to be very skewed.
8)
A) z
΅
/2
=
1.96
B) z
΅
/2
=
1.812
C) t
΅
/2
=
2.228
D) Neither the normal nor the t distribution applies.
Assume that a sample is used to estimate a population proportion p. Find the margin of error E that corresponds to the

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