Alternatively you can simply extrapolate the straight

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Unformatted text preview: ulate for the activation energy in kJ/mol using the value you obtained for the slope of ln(k) vs. 1/T. Use one of your experimentally determined values of k, the activation energy you determined, and the Arrhenius equation to calculate the value of the rate constant at 25 C. Alternatively, you can simply extrapolate the straight line plot of ln(k) vs. 1/T in your notebook to 1/298 , read off the value of ln(k), and find the inverse of ln k. k(25 C) = _______________ By showing the algebra for combining the Arrhenius equation with the expression for the half-life of a reaction of order zero, one or two, you should convince yourself that a plot of ln(t1/2) vs.1/T will have a slope of +Ea / R as long as the half-life is inversely related to the rate constant. Use this information to answer the following question. Does the proportionality constant between half-life and inverse rate constant affect the slope of a plot of ln(t1/2) vs. 1/T? 2 choices given. For many reactions near room temperature, the rate and the rate constant ap...
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