Signal Processing and Linear Systems-B.P.Lathi copy

# Signal Processing and Linear Systems-B.P.Lathi copy

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Unformatted text preview: he components in this band of l lF (in hertz) 2 IS 1F (w ) 1 llF. T he total signal energy is t he sum of energies of all such bands and is indicated by t he a rea under IF(w Was in Eq. (4.63). Therefore, IF(w)1 2 is t he e nergy s pectral d ensity (per unit bandwidth in hertz). For real signals, F(w) a nd F ( - w) are conjugates, and IF(w)1 2 is a n even function of w because IF(w)12 = F(w)F*(w) = F (w)F(-w) w2 t ::.Ej=IF(w)1 2 dw 11" w, 00 - 00 (4.65) Therefore, Eq. (4.63) can be expressed ast dt Here we used t he fact t hat f *(t), being t he conjugate of f (t), can be expressed as t he c onjugate of t he r ight-hand side of Eq. (4.8b). Now, interchanging t he o rder of integration yields 1 = 211" l lw 2 ;- = l lF Hz (4.63) (4.67) t I? Eq: (4.66) i t is ?Ssumed t hat F(w) does not c ontain a n impulse a t w = O. I f s uch a n impulse eXISts, It s hould b e m tegrated s eparately with a mUltiplying factor of 1/211" r ather t han l/rr. 4 2 76 Continuous- Time S ignal Analysis: T he F ourier T ransform • E xample 4 .16 F ind the energy of signal jet) = e-a'u(t). Determine the frequency W ( rad/s) so t hat t he energy contributed by t he spectral components of all the frequencies below W is 95% of the signal energy E j . We have 4.7 Application t o C ommunications: A mplitude M odulation Suppression of all t he s pectral c omponents o f j et) b eyond t he e ssential bandwidth r esults in a signal j et), which is a close a pproximation o f j et). I f we use t he 95% criterion for t he e ssential b andwidth, t he e nergy of t he e rror ( the difference) j et) - jet) is 5% o f E f . Energy Spectral Density From Autocorrelation Function C orrelation of a function j et) w ith i tself is its a utocorrelation f unction ,pf(t), which, for a real j et), is given by [see Eq. (3.32)] We c an verify t his result by Parseval's theorem. For this signal 1 F (w)=-.- ,pJ(t) = Jw+a a nd 1 = r1r 0 1 00 00 Ej ! F(w) I d w 2 1 = ;: 0 1 1 + a2 dw = ~ t an -1 W ;; 1 0 = 21a T he band w = 0 to w = W contains 95% of the signa! energy, t hat is, 0 .95/2a. Therefore, from E q. (4.67) with W 1 = 0 and W 2 = W , we obtain 0.95 _ 2a - .rr!.lW ~ = 2ra tan-1 ~IW = 2ra tan-1 W .. .. + r r 0 w2 a2 a a 0 or 0.95rr = t an-1 W = =} W = 12.706a r ad/s 2 a This result indicates t hat the spectral components of jet) in the band from 0 (dc) to 1 2.706a r ad/s ( 2.02a Hz) contribute 95% o f t he t otal signa! energy; all t he remaining spectral components (in the band from 1 2.706a r ad/s to 00) contribute only 5% o f the signal energy. £::, • E xercise E 4.13 Use Parseval's theorem to show that the energy of the signal 2a J(t) = t2 + a 2 is ~. Hint: Find F (w) using pair 3 and the symmetry property. 1: j (x)j(x - t) dx (4.68a) Also, from Eq. (3.31) w ith get) = j et), i t follows t hat 00 w2 277 'V T he Essential B andwidth o f a Signal S pectra o f m ost o f t he s ignals e xtend t o infinity. However, b ecause t he e nergy o f a ny p ractical s ignal is finite, t he s ignal s pectrum m ust a pproach 0 a s w -...
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## This note was uploaded on 04/14/2013 for the course ENG 350 taught by Professor Bayliss during the Spring '13 term at Northwestern.

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