Unformatted text preview: t he u nit circle in t he ,,(plane.
N ext consider t he signal e Ak , where A lies in t he lefthalf plane in Fig. 8.5a.
This means A = a + j b, where a is negative (a < 0). In this case, t he signal decays
exponentially. This signal can be expressed as " (k, where 545 jrl o o 2 3 3 (a) a nd
because l ejbl "( k (b) 1 =1 Also, a is n egative (a < 0). Hence, hi = ea < 1. T his result means t hat t he corresponding'Y lies inside t he u nit circle. Therefore, a signal " (k decays exponentially
if"( lies w ithin t he u nit circle (Fig. 8.5b). If, in t he above case we h ad selected a
t o b e p ositive, (A in t he r ighthalf plane), t hen hi > 1, a nd "( lies outside t he u nit
circle. Therefore, a signal " (k grows exponentially if "( lies outside t he u nit circle
( Fig.8.5b).
To summarize, t he i maginary axis in t he Aplane m aps into t he u nit circle in the
,,(plane. T he lefthalf plane in t he Aplane m aps into the inside of t he u nit circle and
t he r ighthalf of t he Aplane m aps into t he outside of the u nit circle in t he ,,(plane,
as depicted i n Fig. 8.5. This fact means t hat t he signal " (k grows exponentially with
k if "( is o utside t he u nit circle (h I > 1), a nd decays exponentially if "( is inside the
u nit circle (hi < 1). T he signal is constant or oscillates with constant amplitude if
"( is o n t he u nit circle (hi = 1).
O bserve t hat
(8.4) Figures 8.6a a nd 8.6b show plots of (0.8)k, a nd ( 0.8)k, respectively. Figures
8.6c and 8.6d show plots of (0.5)k, a nd (1.1)k, respectively. These plots verify our
earlier conclusions a bout.the location of"( a nd t he n ature of signal growth. Observe
t hat a signal (_,,()k a lternates sign successively (is positive for even values of k and
negative for o dd values of k , as depicted in Fig. 8.6b). Also, t he e xponential (0.5)k
decays faster t han (0.8)k. T he e xponential (0.5)k can also be expressed as 2  k
because ( 0.5)1 = 2 [see Eq. (8.4)J. ( U)t o E xercise E S.l S ketch s ignals (a) ( l)k (b) ( _l)k (c) (0.5)k (d) ( 0.5)k ( e)(0.5)k (f) 2  k (g) ( _2)k.
E xpress t hese e xponentials as "Ik, a nd p lot "I i n t he c omplex plane for each case . . Verify t hat "Ik
d ecays e xponentially w ith k if "I lies inside t he u nit circle, a nd t hat "(k grows w ith k i f "I is outside
t he u nit circle. I f "I is o n t he u nit circle, "Ik is c onstant o r oscillates w ith a c onstant a mplitude.
Hint: ( l)k = 1 for all k. However, ( _l)k = 1 for even values of k a nd is  1 for o dd values of
k. T herefore, ( _ l)k s witches back a nd f orth from 1 t o  1 (oscillates w ith a c onstant a mplitude).
Note also t hat E q. (8.4) yields ( 0.5)k = 2k 'V 2 3 4 5 6 k 0 1 2 (c) f::,. 3 4 5 6 k (d) F ig. S .6 d iscretetime e xponentials " (k. E xercise E S.2 ( a) Show t hat (i) ( 025)k  4k C ) 4 k
k
2t
(0.1353)t = ( 7.389)t ( v) e3k = ( 20086)k 1(1.)  1 ';k (0.25) (ii~...
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This note was uploaded on 04/14/2013 for the course ENG 350 taught by Professor Bayliss during the Spring '13 term at Northwestern.
 Spring '13
 Bayliss
 Signal Processing, The Land

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