Unformatted text preview: sin 0 dO)1I"R2in2 0, and the total dipole moment of the
s
1~,
1
1
shell isV.A 7I"S2 = pvv. (~) 7I"S2p 71"(2.5 = ~(V .J) x 104) (~). But thecm/s, term about 33 cm/hr. J(r')
(a) J = = ~;
(b)
=>v = dr'. =V. (~) x 103)(1.4 +J. V 9.1 X 103 first or is zero, because This
is astonishingly smallliterally slower than a snail's pace.
Po 1112
m a functionof the source= (4/3)aUJ1I"R\ or 1m = ~aUJR4 i.1 And since ~ = r  r', V (~) =  V' (~). So
fo"
is = aUJ1I"R4 sin3 Ode coordinates, not the field coordinates.
= (471" X A
271"
The (c) From term 5;37,the multi pole expansion for107) is = 2 X 107 N/cm.
dipole Eq. in 1m = 271" d
there = I I I I 2~O + p)ss
(p+ = [(vz) x (110P2VS
J;)] = ~Op_V2ss ~ p+ + p = p(fOI10V2) = p (~:) . ~;, Evidently p+ = p (1 ~:) =
or p = _,2p+. In this naive model, the mobile negative charges fill a
smaller inner cylinder, leaving a shell of positive (stationary) charge at the outside. But since v « c, the effect
is extremely small.
Problem 5.39
(a) If positive charges flow to t...
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This note was uploaded on 04/23/2013 for the course PHSX 531 taught by Professor Chiu during the Fall '12 term at Kansas.
 Fall '12
 chiu

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