J x 104 but thecms term about 33 cmhr jr a j

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Unformatted text preview: sin 0 dO)1I"R2in2 0, and the total dipole moment of the s 1~, 1 1 shell isV.A 7I"S2 = pvv. (~) 7I"S2p 71"(2.5 = ~(V .J) x 104) (~). But thecm/s, term about 33 cm/hr. J(r') (a) J = = ~; (b) =>v = dr'. =V. (~) x 10-3)(1.4 +J. V 9.1 X 10-3 first or is zero, because This is astonishingly small-literally slower than a snail's pace. Po 1112 m a functionof the source= (4/3)aUJ1I"R\ or 1m = ~aUJR4 i.1 And since ~ = r - r', V (~) = - V' (~). So fo" is = aUJ1I"R4 sin3 Ode coordinates, not the field coordinates. = (471" X A 271" The (c) From term 5;37,the multi pole expansion for10-7) is = 2 X 10-7 N/cm. dipole Eq. in 1m = 271" d there- = I I I I 2~O + p-)ss (p+ =- [(vz) x (110P2-VS J;)] = ~Op_V2ss ~ p+ + p- = p-(fOI10V2) = p- (~:) . ~;, Evidently p+ = -p- (1- ~:) = or p- = _,2p+. In this naive model, the mobile negative charges fill a smaller inner cylinder, leaving a shell of positive (stationary) charge at the outside. But since v « c, the effect is extremely small. Problem 5.39 (a) If positive charges flow to t...
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