{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

Physics Solution Manual for 1100 and 2101

# In a step down transformer the voltage across the

This preview shows page 1. Sign up to view the full content.

This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: e induced field, therefore, must be into the paper. The current in the coil must be clockwise . b. At position 2 the magnetic field is directed into the paper and is decreasing as the coil moves away from the wire. The induced magnetic field, therefore, must be directed into the paper, so the current in the coil must be clockwise . ______________________________________________________________________________ 36. REASONING According to Lenz’s law, the induced current in the triangular loop flows in such a direction so as to create an induced magnetic field that opposes the original flux change. SOLUTION a. As the triangle is crossing the +y axis, the magnetic flux down into the plane of the paper is increasing, since the field now begins to penetrate the loop. To offset this increase, an induced magnetic field directed up and out of the plane of the paper is needed. By applying RHR-2 it can be seen that such an induced magnetic field will be created within the loop by a counterclockwise induced current . b. As the triangle is crossing the −x axis, there is no flux change, since all parts of the triangle remain in the magnetic field, which remains constant. Therefore, there is no induced magnetic field, and no induced current appears . c. As the triangle is crossing the −y axis, the magnetic flux down into the plane of the paper is decreasing, since the loop now begins to leave the field region. To offset this decrease, an induced magnetic field directed down and into the plane of the paper is needed. By applying RHR-2 it can be seen that such an induced magnetic field will be created within the loop by a clockwise induced current . Chapter 22 Problems 1215 d. As the triangle is crossing the +x axis, there is no flux change, since all parts of the triangle remain in the field-free region. Therefore, there is no induced magnetic field, and no induced current appears . 37. REASONING The current I in the straight wire produces Table top Region 1 a circular pattern of magnetic field lines around the wire. The magnetic field at any point is tangent to one of these circular field lines. Thus, the field points perpendicular to I the plane of the table. Furthermore, according to RightHand Rule No. 2, the field is directed up out of the table surface in region 1 above the wire and is directed down Region 2 into the table surface in region 2 below the wire (see the drawing at the right). To deduce the direction of any induced current in the circular loop, we consider Faraday’s law and the change that occurs in the magnetic flux through the loop due to the field of the straight wire. SOLUTION As the current I decreases, the magnitude of the field that it produces also decreases. However, the directions of the fields in regions 1 and 2 do not change and remain as discussed in the reasoning. Since the fields in these two regions always have opposite directions and equal magnitudes at any given radial distance from the straight wire, the flux through the regions add up to give zero for any value of the current. With the flux remaining constant as time passes, Faraday’s law indicates that there is no induced emf in the coil. Since there is no induced emf in the coil, there is no induced current . ______________________________________________________________________________ 38. REASONING AND SOLUTION If the applied magnetic field is decreasing in time, then the flux through the circuit is decreasing. Lenz's law requires that an induced magnetic field be produced which attempts to counteract this decrease; hence its direction is out of the paper. The sense of the induced current in the circuit must be CCW. Therefore, the lower plate of the capacitor is positive while the upper plate is negative. The electric field between the plates of the capacitor points from positive to negative so the electric field points upward . ______________________________________________________________________________ 39. REASONING AND SOLUTION a. Location I As the loop swings downward, the normal to the loop makes a smaller angle with the applied field. Hence, the flux through the loop is increasing. The induced magnetic field must point generally to the left to counteract this increase. The induced current flows x→y→z 1216 ELECTROMAGNETIC INDUCTION Location II The angle between the normal to the loop and the applied field is now increasing, so the flux through the loop is decreasing. The induced field must now be generally to the right, and the current flows z→ y→ x b. Location I The argument is the same as for location II in part a. z→ y→ x Location II The argument is the same as for location I in part a. x→y→z ______________________________________________________________________________ 40. REASONING When the motor is running at normal speed, the current is the net emf divided by the resistance R of the armature wire. The net emf is the applied voltage V minus the back emf developed by the rotating coil. We can use this relation to find the back e...
View Full Document

{[ snackBarMessage ]}

Ask a homework question - tutors are online