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Theseareoftenreferredtoasinitialvalueproblemstosolve

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Unformatted text preview: n a kx a kx dx = + C, k ≠ 0 ∫ k ( ln a ) Rule 6: Integral of the Function x −1 1 ∫ x dx = ∫ x dx = ln x + C −1 When we are given the derivative of the function and the coordinates of a single point of the function, we can actually determine the exact function (not up to some constant). These are often referred to as initial value problems. To solve them, we first find the antiderivative, then use the added information to determine the value of the constant. Examp...
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This note was uploaded on 05/01/2013 for the course MATH 1081 taught by Professor Johanson during the Spring '08 term at Colorado.

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