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Stitz-Zeager_College_Algebra_e-book

# 1 3 21 1 3 21 110 asymptotes y 11 x 1 3 9 8 7 6 5 4 3

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Unformatted text preview: x (5, 2) Focus (5, −1) Directrix y = 5 (c) (x + 1)2 = 8(y − 6) Vertex (−1, 6) Focus (−1, 8) Directrix y = 4 (f) y − 9 = − 4 (x − 2) 2 3 9 Vertex 2, 2 Focus 5 , 9 32 7 Directrix x = 3 1 (b) x + 2 = − 5 (y − 1) 5 2 Vertex − 5 , 1 2 19 Focus − 5 , 20 Directrix y = 21 20 3. (a) y 2 = −28(x − 7) (b) (x + 8)2 = 64 (y + 9) 9 (c) (y − 1)2 = 10 x − 15 2 2 (d) (x − 1)2 = 6 y + 17 or 2 (x − 1)2 = −6 y + 11 2 4. The bulb should be placed 0.625 centimeters above the vertex of the mirror. (This actually checks out, folks!) 5. The receiver should be placed 5.0625 centimeters above the vertex of the cross section of the antenna. 7.4 Ellipses 7.4 419 Ellipses In the deﬁnition of a circle, Deﬁnition 7.1, we ﬁxed a point called the center and considered all of the points which were a ﬁxed distance r from that one point. For our next conic section, the ellipse, we ﬁx two distinct points and a distance d to use in our deﬁnition. Definition 7.4. Given two distinct points F1 and F2 in the plane and a ﬁxed distance d, an ellipse i...
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