Stitz-Zeager_College_Algebra_e-book

1 3 21 1 3 21 110 asymptotes y 11 x 1 3 9 8 7 6 5 4 3

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Unformatted text preview: x (5, 2) Focus (5, −1) Directrix y = 5 (c) (x + 1)2 = 8(y − 6) Vertex (−1, 6) Focus (−1, 8) Directrix y = 4 (f) y − 9 = − 4 (x − 2) 2 3 9 Vertex 2, 2 Focus 5 , 9 32 7 Directrix x = 3 1 (b) x + 2 = − 5 (y − 1) 5 2 Vertex − 5 , 1 2 19 Focus − 5 , 20 Directrix y = 21 20 3. (a) y 2 = −28(x − 7) (b) (x + 8)2 = 64 (y + 9) 9 (c) (y − 1)2 = 10 x − 15 2 2 (d) (x − 1)2 = 6 y + 17 or 2 (x − 1)2 = −6 y + 11 2 4. The bulb should be placed 0.625 centimeters above the vertex of the mirror. (This actually checks out, folks!) 5. The receiver should be placed 5.0625 centimeters above the vertex of the cross section of the antenna. 7.4 Ellipses 7.4 419 Ellipses In the definition of a circle, Definition 7.1, we fixed a point called the center and considered all of the points which were a fixed distance r from that one point. For our next conic section, the ellipse, we fix two distinct points and a distance d to use in our definition. Definition 7.4. Given two distinct points F1 and F2 in the plane and a fixed distance d, an ellipse i...
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This note was uploaded on 05/03/2013 for the course MATH Algebra taught by Professor Wong during the Fall '13 term at Chicago Academy High School.

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