Stitz-Zeager_College_Algebra_e-book

# 1 example 161 let f x 6x2 2x and g x 3 1 find

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Unformatted text preview: functions did you ﬁnd that failed to satisfy the conditions above? Did f (x) = x2 √ 1 work? What about f (x) = x or f (x) = 3x + 7 or f (x) = ? Did you ﬁnd an attribute x common to those functions that did succeed? You should have, because there is only one extremely special family of functions that actually works here. Thus we return to our previous statement, in general, f (a + b) = f (a) + f (b). 1.5 Function Notation 1.5.2 53 Answers 4 1. f (x) = √ x − 13 Domain: [0, 169) ∪ (169, ∞) 4 x − 13 Domain: (13, ∞) 2. g (x) = √ 5. (a) 2 (b) 6 (c) 6. (a) (b) (c) (d) (e) 7. (a) (b) (c) (d) (e) 1 − 4 2 27 −2 16 27 1 32x3 8 x3 4 3. h(x) = √ − 13 x Domain: (0, ∞) 4 − 13 x Domain: (0, ∞) 4. k (x) = (d) 16x2 − 12x + 2 (g) x2 − 11x + 30 (e) 4x2 − 12x + 8 (h) x2 − 3x − 2 (f) x2 + 3x + 2 (i) x4 − 3x2 + 2 2 x3 2 2 =3 (g) (x − 4)3 x − 12x2 + 48x − 64 2 2 − 4x3 (h) 3 − 4 = x x3 2 (i) 6 x (f) − (f) 3a2 + 3a + 14 16 4 12a2 + 6a − 2 6a2 + 6a − 4 3a2 + 15a + 16 8. (a) f (−4) = 1 (b) f (−...
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## This note was uploaded on 05/03/2013 for the course MATH Algebra taught by Professor Wong during the Fall '13 term at Chicago Academy High School.

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