1 this makes these graphs easier to visualize than

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: rcise 4 from Section 10.5. We find √ cos(t) + 3 sin(t) = 2 sin t + π so that x(t) = 10e−t/5 sin t + π . Graphing this on the 3 3 calculator as y = 10e−x/5 sin x + π reveals some interesting behavior. The sinusoidal nature 3 continues indefinitely, but it is being attenuated. In the sinusoid A sin(ωx + φ), the coefficient A of the sine function is the amplitude. In the case of y = 10e−x/5 sin x + π , we can think 3 of the function A(x) = 10e−x/5 as the amplitude. As x → ∞, 10e−x/5 → 0 which means the amplitude continues to shrink towards zero. Indeed, if we graph y = ±10e−x/5 along with y = 10e−x/5 sin x + π , we see this attenuation taking place. This equation corresponds to 3 the motion of an object on a spring where there is a slight force which acts to ‘damp’, or slow the motion. An example of this kind of force would be the friction of the object against the air. In this model, the object oscillates forever, but with smaller and smaller amplitude. y = 10e−x/5 sin x...
View Full Document

{[ snackBarMessage ]}

Ask a homework question - tutors are online