Stitz-Zeager_College_Algebra_e-book

13 to the 3 3 matrix a 0 1 2 1 4 3 1 2 5 deta det

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Unformatted text preview: illustrates. 2 −1 + 5A 3 5 using the definitions and properties of matrix arithmetic. Example 8.3.1. Solve for the matrix A: 3A − = −4 2 6 −2 + 1 3 9 12 −3 39 480 Systems of Equations and Matrices Solution. 2 −1 3 5 3A − 3A + 2 −1 3 5 = −4 2 6 −2 + 5A = −4 2 6 −2 + + (−1)(5A) = −1 6 5 11 + ((−1)(5))A = 9 12 −3 39 −1 6 5 11 + (−1)(5A) = 1 3 + −1 6 5 11 2 −1 3 5 (−1)(2) (−1)(−1) (−1)(3) (−1)(5) 3A + + + 5A 2 −1 3 5 3A + (−1) 3A + (−1) −4 2 6 −2 2 −1 3 5 3A + − 3A + (−1) = −2 1 −3 −5 + 5A + (−5)A = 1 3 1 3 34 −1 13 −1 6 5 11 = −1 6 5 11 = −1 6 5 11 +− (−2)A + 02×2 = −1 6 5 11 − 3A + (−5)A + (3 + (−5))A + −2 1 −3 −5 +− (9) (−3) −2 1 −3 −5 −2 1 −3 −5 −2 1 −3 −5 −2 1 −3 −5 (−2)A = −1 − (−2) 6−1 5 − (−3) 11 − (−5) (−2)A = 15 8 16 − 1 ((−2)A) = − 1 2 2 15 8 16 1 − 2 (−2) A = − 1 (1) 2 − 1 (8) 2 1A = −1 −5 2 2 −4 − 16 2 A= 1 ...
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This note was uploaded on 05/03/2013 for the course MATH Algebra taught by Professor Wong during the Fall '13 term at Chicago Academy High School.

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