{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

Stitz-Zeager_College_Algebra_e-book

# 17 graphs of functions 172 77 exercises 1 sketch the

This preview shows page 1. Sign up to view the full content.

This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: constitute the range of f . Hence, our answer is [−3, 3]. 3. Since the graph of f is the graph of the equation y = f (x), f (2) is the y -coordinate of the point which corresponds to x = 2. Since the point (2, 0) is on the graph, we have f (2) = 0. 74 Relations and Functions 4. The x-intercepts are the points on the graph with y -coordinate 0, namely (−2, 0) and (2, 0). 5. The y -intercept is the point on the graph with x-coordinate 0, namely (0, 3). 6. The zeros of f are the x-coordinates of the x-intercepts of the graph of y = f (x) which are x = −2, 2. 7. To solve f (x) < 0, we look for the x values of the points on the graph where the y -coordinate is less than 0. Graphically, we are looking where the graph is below the x-axis. This happens for the x values from −4 to −2 and again from 2 to 4. So our answer is [−4, −2) ∪ (2, 4]. 8. To ﬁnd where f (x) = 1, we look for points on the graph where the y -coordinate is 1. Even though these points aren’t speciﬁed, we see that the curve has two...
View Full Document

{[ snackBarMessage ]}

Ask a homework question - tutors are online