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Unformatted text preview: constitute the range of f . Hence, our answer is [−3, 3].
3. Since the graph of f is the graph of the equation y = f (x), f (2) is the y -coordinate of the
point which corresponds to x = 2. Since the point (2, 0) is on the graph, we have f (2) = 0. 74 Relations and Functions
4. The x-intercepts are the points on the graph with y -coordinate 0, namely (−2, 0) and (2, 0).
5. The y -intercept is the point on the graph with x-coordinate 0, namely (0, 3).
6. The zeros of f are the x-coordinates of the x-intercepts of the graph of y = f (x) which are
x = −2, 2.
7. To solve f (x) < 0, we look for the x values of the points on the graph where the y -coordinate
is less than 0. Graphically, we are looking where the graph is below the x-axis. This happens
for the x values from −4 to −2 and again from 2 to 4. So our answer is [−4, −2) ∪ (2, 4].
8. To ﬁnd where f (x) = 1, we look for points on the graph where the y -coordinate is 1. Even
though these points aren’t speciﬁed, we see that the curve has two...
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