Stitz-Zeager_College_Algebra_e-book

17 graphs of functions 172 77 exercises 1 sketch the

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Unformatted text preview: constitute the range of f . Hence, our answer is [−3, 3]. 3. Since the graph of f is the graph of the equation y = f (x), f (2) is the y -coordinate of the point which corresponds to x = 2. Since the point (2, 0) is on the graph, we have f (2) = 0. 74 Relations and Functions 4. The x-intercepts are the points on the graph with y -coordinate 0, namely (−2, 0) and (2, 0). 5. The y -intercept is the point on the graph with x-coordinate 0, namely (0, 3). 6. The zeros of f are the x-coordinates of the x-intercepts of the graph of y = f (x) which are x = −2, 2. 7. To solve f (x) < 0, we look for the x values of the points on the graph where the y -coordinate is less than 0. Graphically, we are looking where the graph is below the x-axis. This happens for the x values from −4 to −2 and again from 2 to 4. So our answer is [−4, −2) ∪ (2, 4]. 8. To find where f (x) = 1, we look for points on the graph where the y -coordinate is 1. Even though these points aren’t specified, we see that the curve has two...
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