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**Unformatted text preview: **−2, −4 − 11
√ Asymptotes y = ± 30
5 (x + 2) − 4 y 2 x2
−
=1
9
16
(x − 6)2 (y − 5)2
(d)
−
=1
256
64
(c) 5. Sasquatch is located at the point (−0.9629, −0.8113).
6. By placing Station A at (0, −50) and Station B at (0, 50), the two second time diﬀerence
x2
y2
−
= 1 with foci A and B and center (0, 0). Placing Station C
yields the hyperbola
36 2464
at (−150, −50) and using foci A and C gives us a center of (−75, −50) and the hyperbola
(x + 75)2 (y + 50)2
−
= 1. The point of intersection of these two hyperbolas which is closer
225
5400
to A than B and closer to A than C is (−57.8444, −9.21336) so that is the epicenter.
7. (b) y2
x2
−
= 1.
9
27 Chapter 8 Systems of Equations and Matrices
8.1 Systems of Linear Equations: Gaussian Elimination Up until now, when we concerned ourselves with solving diﬀerent types of equations there was only
one equation to solve at a time. Given an equation f (x) = g (x), we could check our solutions
geometrically by ﬁnding where the graphs of y = f (x) and y = g (x) intersect. The x-coordinates
of these intersection points correspond to the solutions to the equation f (x) = g (x), and the y coordinates were largely ignored. If we modify the problem and ask for the intersection points of
the graph...

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