Stitz-Zeager_College_Algebra_e-book

3 choose a real number called a test value in each of

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Unformatted text preview: asing on 5 , ∞ 6 Vertex 5 , 73 is a minimum 6 12 Axis of symmetry x = 5 6 73 12 y 6 5 4 3 2 1 −1 −1 −2 −3 1 2 3 x 152 Linear and Quadratic Functions (h) f (x) = x2 − 1 100 x − 1 = √ 1+ 40001 200 x− 40001 12 200 √ − 40000 1− 40001 200 x-intercepts and y -intercept (0, −1) Domain: (−∞, ∞) 40001 Range: − 40000 , ∞ 1 Decreasing on −∞, 200 1 Increasing on 200 , ∞ 40001 1 Vertex 200 , − 40000 is a minimum8 1 Axis of symmetry x = 200 2. y = |1 − x2 | 7 6 5 4 3 2 1 −2 −1 3. y y 8 1 2 x √ √ 3 − 7 −1 + 7 , , 2 2 √ √ 3 + 7 −1 − 7 , 2 2 7 6 5 4 3 2 1 −2 −1 1 2 x 5. (a) The applied domain is [0, ∞). (d) The height function is this case is s(t) = −4.9t2 + 15t. The vertex of this parabola is approximately (1.53, 11.48) so the maximum height reached by the marble is 11.48 meters. It hits the ground again when t ≈ 3.06 seconds. (e) The revised height function is s(t) = −4.9t2 + 15t + 25 which has zeros at t ≈ −1.20 and t ≈ 4.26. We ignore the negative value and claim that the marble will hit the ground after 4.26 seconds. (f) Shooting down means the initial velocity is neg...
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This note was uploaded on 05/03/2013 for the course MATH Algebra taught by Professor Wong during the Fall '13 term at Chicago Academy High School.

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