Stitz-Zeager_College_Algebra_e-book

6 it suces to show cos cos and sin sin the remaining

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Unformatted text preview: e α, we subtract: α = 2π − θ = 2π − 11π = π . 6 6 Since θ is a Quadrant IV angle, cos(θ) > 0 and sin(θ) < 0, so the Reference Angle Theorem √ gives: cos 11π = cos π = 23 and sin 11π = − sin π = − 1 . 6 6 6 6 2 y y 1 1 θ = 225◦ π 6 x 1 45◦ θ= Finding cos (225◦ ) and sin (225◦ ) 1 x 11π 6 11π 6 Finding cos and sin 11π 6 π π 3. To plot θ = − 54 , we rotate clockwise an angle of 54 from the positive x-axis. The terminal π side of θ, therefore, lies in Quadrant II making an angle of α = 54 − π = π radians with 4 respect to the negative x-axis. Since θ is a Quadrant II angle, the Reference Angle Theorem √ √ π π gives: cos − 54 = − cos π = − 22 and sin − 54 = sin π = 22 . 4 4 π π 4. Since the angle θ = 73 measures more than 2π = 63 , we find the terminal side of θ by rotating π one full revolution followed by an additional α = 73 − 2π = π radians. Since θ and α are 3 coterminal, cos 7π 3 = cos π 3 = 1 2 and sin 7π 3 = sin π 3 √ = 3 2. y y 1 1 θ= π 4 1 π 3...
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This note was uploaded on 05/03/2013 for the course MATH Algebra taught by Professor Wong during the Fall '13 term at Chicago Academy High School.

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