Stitz-Zeager_College_Algebra_e-book

732 the solution 1 3 0 which means if substituted into

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Unformatted text preview: nition 5.5, we can rewrite the cube root as a 1 exponent. We begin by using the Power 3 350 Exponential and Logarithmic Functions Rule1 , and we keep in mind that the common log is log base 10. log 3 100x2 yz 5 100x2 yz 5 100x2 1 log 3 yz 5 1/3 = log = = = = = = = = 1 3 1 3 1 3 1 3 1 3 2 3 2 3 Power Rule log 100x2 − log y z 5 Quotient Rule 1 log 100x2 − 3 log y z 5 1 5 3 log(y ) + log z 1 1 log(100) + 3 log x2 − 3 log(y ) − 1 log z 5 3 2 1 5 log(100) + 3 log(x) − 3 log(y ) − 3 log(z ) 1 + 2 log(x) − 3 log(y ) − 5 log(z ) 3 3 2 log(x) − 1 log(y ) − 5 log(z ) + 3 3 3 log(100) + log x2 − Product Rule Power Rule Since 102 = 100 5. At first it seems as if we have no means of simplifying log117 x2 − 4 , since none of the properties of logs addresses the issue of expanding a difference inside the logarithm. However, we may factor x2 − 4 = (x + 2)(x − 2) thereby introducing a product which gives us license to use the Product Rule. log117 x2 − 4 = log117 [(x + 2)(x − 2)] Factor = log117 (x...
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This note was uploaded on 05/03/2013 for the course MATH Algebra taught by Professor Wong during the Fall '13 term at Chicago Academy High School.

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