As a result we have our last result of the section

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Unformatted text preview: finding the zeros and checking the sign of f using test values, we are using test values to determine where the signs switch to find the zeros. It is a slow and tedious, yet fool-proof, method for determining an approximation of a real zero. Our last example reminds us that finding the zeros of polynomials is a critical step in solving polynomial equations and inequalities. Example 3.3.7. 1. Find all of the real solutions to the equation 2x5 + 6x3 + 3 = 3x4 + 8x2 . 2. Solve the inequality 2x5 + 6x3 + 3 ≤ 3x4 + 8x2 . 3. Interpret your answer to part 2 graphically, and verify using a graphing calculator. Solution. 1. Finding the real solutions to 2x5 + 6x3 + 3 = 3x4 + 8x2 is the same as finding the real solutions to 2x5 − 3x4 + 6x3 − 8x2 + 3 = 0. In other words, we are looking for the real zeros of p(x) = 2x5 − 3x4 + 6x3 − 8x2 + 3. Using the techniques developed in this section, we divide as follows. 5 We don’t use this word lightly; it can be proven that the zeros of some polynomials cannot be expressed using...
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This note was uploaded on 05/03/2013 for the course MATH Algebra taught by Professor Wong during the Fall '13 term at Chicago Academy High School.

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