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Unformatted text preview: re we go again... 122 Linear and Quadratic Functions 1. Since R = xp, we substitute p(x) = −1.5x + 250 from Example 2.1.6 to get
R(x) = x(−1.5x + 250) = −1.5x2 + 250x
2. Using Deﬁnition 2.3, we get the average rate of change is
R(50) − R(0)
8750 − 0
50 − 0
50 − 0
Interpreting this slope as we have in similar situations, we conclude that for every additional
PortaBoy sold during a given week, the weekly revenue increases $175.
3. The wording of this part is slightly diﬀerent than that in Deﬁnition 2.3, but its meaning is to
ﬁnd the average rate of change of R over the interval [50, 100]. To ﬁnd this rate of change,
R(100) − R(50)
10000 − 8750
100 − 50
In other words, for each additional PortaBoy sold, the revenue increases by $25. Note while
the revenue is still increasing by selling more game systems, we aren’t getting as much of an
increase as we did in part 2 of this example. (Can you think of why this would hap...
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