Factoring approach from rx 32 x13 x2 x23 we

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: ossibility, but we also get the possibility that c = 2 − d. This suggests that f may not be one-to-one. Taking d = 0, we get c = 0 or c = 2. With f (0) = 4 and f (2) = 4, we have produced two different inputs with the same output meaning f is not one-to-one. (b) We note that h is a quadratic function and we graph y = h(x) using the techniques presented in Section 2.3. The vertex is (1, 3) and the parabola opens upwards. We see immediately from the graph that h is not one-to-one, since there are several horizontal lines which cross the graph more than once. 4. (a) The function F is given to us as a set of ordered pairs. The condition F (c) = F (d) means the outputs from the function (the y -coordinates of the ordered pairs) are the same. We see that the points (−1, 1) and (2, 1) are both elements of F with F (−1) = 1 and F (2) = 1. Since −1 = 2, we have established that F is not one-to-one. (b) Graphically, we see the horizontal line y = 1 crosses the graph more than once. Hence, the graph of F fails the Horizontal Line Test. 5.2 Inverse Functions 299 y 6 y 5 4 2 3 1 x 2 −2 −1 1 2 1 y = F (x) 1 2 x −1 y = h(x) We have shown that the functions f and g in Example 5.2.1 are one-to-one. This means they are invertible, so it i...
View Full Document

This note was uploaded on 05/03/2013 for the course MATH Algebra taught by Professor Wong during the Fall '13 term at Chicago Academy High School.

Ask a homework question - tutors are online