Stitz-Zeager_College_Algebra_e-book

Finally we get t 12 this means it will 5 take 12

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Unformatted text preview: (x2 − 4x + 13) = (3x − 1)(x − (2 + 3i))(x − (2 − 3i)) 1 Zeros: x = , x = 2 ± 3i 3 √ √ 4 + 9x2 + 20 = x2 + 4 x2 + 5 = (x − 2i)(x + 2i) x − i 5 x + i 5 (e) x √ Zeros: x = ±2i, ±i 5 √ √ 2 12 (f) 4x4 − 4x3 + 13x2 − 12x + 3 = x − 2 4x2 + 12 = 4 x − 1 (x + i 3)(x − i 3) 2 √ 1 Zeros: x = , x = ± 3i 2 3 + 3x2 + 4x + 12 = (x + 3) x2 + 4 = (x + 3)(x + 2i)(x − 2i) (g) x Zeros: x = −3, ±2i (h) 2x4 − 7x3 + 14x2 − 15x + 6 = (x − 1)2 2x2 − 3x + 6 √ √ 3 39 3 39 2 x− = 2(x − 1) + i x− − i 4 4 4 4 √ 3 39 Zeros: x = 1, x = ± i 4 4 3.4 Complex Zeros and the Fundamental Theorem of Algebra (i) 4x3 − 6x2 − 8x + 15 = (k) (l) (m) (n) (o) (p) (q) (r) 3 2 4x2 − 12x + 10 = 31 31 +i x− −i 22 22 3 31 Zeros: x = − , x = ± i 2 22 x4 + x3 + 7x2 + 9x − 18 = (x + 2)(x − 1) x2 + 9 = (x + 2)(x − 1)(x + 3i)(x − 3i) Zeros: x = −2, 1, ±3i √ √ 3 1 x− x − −2 + 2 2 x − −2 − 2 2 6x4 +17x3 − 55x2 +16x +12 = 6 x + 3 2 √ 1 3 Zeros: x = − , x = , x = −2 ± 2 2 3 2 x5 − x4 + 7x3 − 7x2 + 12x − 12 = (x − 1) x2 + 3 x2 + 4 √ √ 3)( = (x − 1)(x − i √ x + i 3)(x − 2i)(x + 2i) Zeros: x = 1, ± 3i, ±2i √ √ 29 5 29 3 + 7x2 + 9x − 2 = (x + 2) x − − 5 + x x− − − 2...
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This note was uploaded on 05/03/2013 for the course MATH Algebra taught by Professor Wong during the Fall '13 term at Chicago Academy High School.

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