Stitz-Zeager_College_Algebra_e-book

Find two other forms of the parametric solution to

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Unformatted text preview: 1.9. For simplicity, we assume the hyperbola is centered at (0, 0) with its foci at (−5, 0) and (5, 0). Schematically, we have 7.5 Hyperbolas 441 y 6 5 4 3 2 1 Jeff −6 −5 −4 −3 −2 −1 −1 Carl 1 2 3 4 5 6 x −2 −3 −4 −5 −6 2 2 We are seeking a curve of the form x2 − y2 = 1 in which the distance from the center to each focus a b is c = 5. As we saw in the derivation of the standard equation of the hyperbola, Equation 7.6, d = 2a, so that 2a = 1.9, or a = 0.95 and a2 = 0.9025. All that remains is to find b2 . To that end, we recall that a2 + b2 = c2 so b2 = c2 − a2 = 25 − 0.9025 = 24.0975. Since Sasquatch is closer to 2 x2 Jeff than it is to Carl, it must be on the western (left hand) branch of 0.9025 − 24.y 0975 = 1. In our previous example, we did not have enough information to pin down the exact location of Sasquatch. To accomplish this, we would need a third observer. Example 7.5.5. By a stroke of luck, Kai was also camping in the woods during the events of the previous example. He was located 6 miles due north of Jeff and heard the Sa...
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