Stitz-Zeager_College_Algebra_e-book

Stitz-Zeager_College_Algebra_e-book

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Solution. 450 1. N (0) = 500 − 1+3(0) = 50. This means that at the beginning of the semester, 50 students have had the flu. 450 450 2. We set N (t) = 300 to get 500 − 1+3t = 300 and solve. Isolating the fraction gives 1+3t = 200. 5 Clearing denominators gives 450 = 200(1 + 3t). Finally, we get t = 12 . This means it will 5 take 12 months, or about 13 days, for 300 students to have had the flu. 3. To determine the behavior of N as t → ∞, we can use a table. 8 The graph does, however, seem to resemble a non-constant line as x → ±∞. We will discuss this phenomenon in the next section. 9 Using techniques you’ll see in Calculus. 4.1 Introduction to Rational Functions t 10 100 1000 10000 241 N (t) ≈ 485.48 ≈ 498.50 ≈ 499.85 ≈ 499.98 The table suggests that as t → ∞, N (t) → 500. (More specifically, 500− .) This means as time goes by, only a total of 500 students will have ever had the flu. 242 Rational Functions 4.1.1 Exercises 1. For each rational function f given belo...
View Full Document

This note was uploaded on 05/03/2013 for the course MATH Algebra taught by Professor Wong during the Fall '13 term at Chicago Academy High School.

Ask a homework question - tutors are online