Stitz-Zeager_College_Algebra_e-book

For the second region r 0 r 2 2 sin picks 6 2 up

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Unformatted text preview: 1, we have all three angles and all three sides 1 to work with. However, to minimize propagated error, we choose A = 2 ac sin(β ) from Theorem 11.4 because it uses the most pieces of given information. We are given a = 7 and β = 45◦ , and we ◦) ◦) calculated c = 7 sin(15◦ ) . Using these values, we find A = 1 (7) 7 sin(15◦ ) sin (45◦ ) =≈ 5.18 square 2 sin(120 sin(120 units. The reader is encouraged to check this answer against the results obtained using the other formulas in Theorem 11.4. 11 Or by Theorem 10.4 again . . . 11.2 The Law of Sines 11.2.1 769 Exercises 1. Solve for the remaining side(s) and angle(s) if possible. (a) α = 13◦ , β = 17◦ , a = 5 (k) α = 42◦ , a = 39, b = 23.5 (b) α = 73.2◦ , β = 54.1◦ , a = 117 (l) α = 6◦ , a = 57, b = 100 (c) α = 95◦ , β = 85◦ , a = 33.33 (m) γ = 53◦ , α = 53◦ , c = 28.01 (d) α = 95◦ , β = 62◦ , a = 33.33 (n) β = 102◦ , b = 16.75, c = 13 (e) α = 117◦ , a = 35, b = 42 (o) β = 102◦ , b = 16.75, c = 18 (f) α = 117◦ , a = 45, b = 42 (p) β = 102◦ , γ = 35◦ ,...
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