{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

Stitz-Zeager_College_Algebra_e-book

For these points 6 cos2 3 or cos2 1 solving we

Info icon This preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 138.19◦ . At 3 3 3 this point, we pause to see if it makes sense that we actually have two viable cases to consider. As we have discussed, both candidates for γ are ‘compatible’ with the given angle-side pair 11.2 The Law of Sines 765 (α, a) = (30◦ , 3) in that both choices for γ can fit in a triangle with α and both have a sine of 2 3 . The only other given piece of information is that c = 4 units. Since c > a, it must be true that γ , which is opposite c, has greater measure than α which is opposite a. In both cases, γ > α, so both candidates for γ are compatible with this last piece of given information as 2 well. Thus have two triangles on our hands. In the case γ = arcsin 3 radians ≈ 41.81◦ , we find5 β ≈ 180◦ − 30◦ − 41.81◦ = 108.19◦◦. Using the Law of Sines with the angle-side opposite pair (α, a) and β , we find b ≈ 3 sin(108.◦19 ) ≈ 5.70 units. In the case γ = π − arcsin 2 radians 3 sin(30 ) ≈ 138.19◦ , we repeat the exact same steps and find β ≈ 11.81◦ and b ≈ 1.23 units.6 Both triangles are d...
View Full Document

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern