Stitz-Zeager_College_Algebra_e-book

However we would consider 2x2 2 f x 2 x 1 to be a

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Unformatted text preview: ), Q(2, 4) 4. P (−3, 2), Q(4, 2) 2. P (−1, 2), Q(3, 4) 5. P (2, 3), Q(2, −1) 3. P (−2, 3), Q(2, −3) 6. P (2, 3), Q(2.1, −1) Solution. In each of these examples, we apply the slope formula, Equation 2.1. y 4 Q 3 1. m= 4−0 4 = =2 2−0 2 2 1 P1 2 3 x 4 y 4 Q 2. 4−2 2 1 m= == 3 − (−1) 4 2 3 2 P 1 −1 3 2 x 1 1 2 y 4 P 3 2 3. −3 − 3 −6 3 m= = =− 2 − (−2) 4 2 1 −3 −2 −1 3 x −1 −2 Q −3 −4 y 3 4. m= 2−2 0 = =0 4 − (−3) 7 2 Q P 1 −4 −3 −2 −1 1 2 3 4 x 2.1 Linear Functions 113 y 3 P 2 1 5. −1 − 3 −4 m= = , which is undefined 2−2 0 1 x 2 −1 Q −2 −3 y 3 P 2 1 6. −1 − 3 −4 m= = = −40 2.1 − 2 0.1 1 −1 x 2 Q −2 −3 A few comments about Example 2.1.1 are in order. First, for reasons which will be made clear soon, if the slope is positive then the resulting line is said to be increasing. If it is negative, we say the line is decreasing. A slope of 0 results in a horizontal line which we say is constant, and an undefined slope results in a vertical line.2 Second, the larger the slope is in absolute value, the steeper the line. You may recall from Intermediate Algebra t...
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This note was uploaded on 05/03/2013 for the course MATH Algebra taught by Professor Wong during the Fall '13 term at Chicago Academy High School.

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