{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

Stitz-Zeager_College_Algebra_e-book

# If we want to make a prot then we need to solve p x 0

This preview shows page 1. Sign up to view the full content.

This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: or c > 0, |x| < c is equivalent to −c < x < c. • For c ≤ 0, |x| < c has no solution. • For c ≥ 0, |x| > c is equivalent to x < −c or x > c. • For c < 0, |x| > c is true for all real numbers. As with Theorem 2.1 in Section 2.2, we could argue Theorem 2.3 using cases. However, in light of what we have developed in this section, we can understand these statements graphically. For instance, if c > 0, the graph of y = c is a horizontal line which lies above the x-axis through (0, c). To solve |x| < c, we are looking for the x values where the graph of y = |x| is below the graph of y = c. We know the graphs intersect when |x| = c, which, from Section 2.2, we know happens when x = c or x = −c. Graphing, we get y (−c, c) −c (c, c) c x We see the graph of y = |x| is below y = c for x between −c and c, and hence we get |x| < c is equivalent to −c < x < c. The other properties in Theorem 2.3 can be shown similarly. Example 2.4.3. Solve the fo...
View Full Document

{[ snackBarMessage ]}

Ask a homework question - tutors are online