Stitz-Zeager_College_Algebra_e-book

Let a abc def e1 01 10 e2 50 01 e3 1 2 0 1 compute

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Unformatted text preview: 3z = 0 7 x − 2y + 3 z = 11 16 y− 5z = −5 (f) z= 1 0 x + y + 2z = y − 3z = 6 (g) 2 z = −2 1 x − 2y + 1z = −1 2 2 3 3 (h) y + 5z = 5 0= 1 x − y + z = −4 y − 7z = 17 (i) z = −2 x − 2y + 2z = −2 1 y= (j) 2 z= 1 Consistent independent Solution (−2, 7) Consistent independent Solution (1, 2, 0) Consistent dependent Solution (−t + 5, −3t + 15, t) for all real numbers t Inconsistent No solution Consistent dependent Solution (−4t − 17, 3t, t) for all real numbers t Consistent independent Solution (2, −1, 1) Consistent independent Solution (1, 3, −2) Inconsistent no solution Consistent independent Solution (1, 3, −2) Consistent independent 1 Solution −3, 2 , 1 8.1 Systems of Linear Equations: Gaussian Elimination x − 1y + 1z = 1 2 2 2 2 (k) y − 3z = 0 z=1 x − 3y − 4z = 3 4 y + 11 z = 13 (l) 13 0= 0 x+y+z = 4 1 y + 2z = 3 (m) 2 0=1 8 x−y+z = y − 2z = −5 (n) z= 1 x − 3y + 1z = −1 2 2 2 (o) y + z = − 11 2 0= 0 16 25 2 x1 + 3 x2 − 3 x3 − x4 = 3 x2 + 4x3 −...
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This note was uploaded on 05/03/2013 for the course MATH Algebra taught by Professor Wong during the Fall '13 term at Chicago Academy High School.

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