Stitz-Zeager_College_Algebra_e-book

Since q lies in quadrant iii 4 we choose 54 which

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Unformatted text preview: 7 t, so we (temporarily) write the height in terms of θ as h = 64 sin (θ) + 72. 4π Subtracting π from θ gives the final answer h(t) = 64 sin θ − π + 72 = 64 sin 127 t − π + 72. We 2 2 2 can check the reasonableness of our answer by graphing y = h(t) over the interval 0, 127 . 2 y 136 72 8 127 2 t A few remarks about Example 11.1.1 are in order. First, note that the amplitude of 64 in our answer corresponds to the radius of the Giant Wheel. This means that passengers on the Giant Wheel never stray more than 64 feet vertically from the center of the Wheel, which makes sense. π/2 Second, the phase shift of our answer works out to be 4π/127 = 127 = 15.875. This represents the 8 ‘time delay’ (in seconds) we introduce by starting the motion at the point P as opposed to the point Q. Said differently, passengers which ‘start’ at P take 15.875 seconds to ‘catch up’ to the point Q. Our next example revisits the daylight data first introduced in Section 2.5, Exercise 4b. 4 We are readjusting our ‘baseline’ from y = 0 to y = 72....
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This note was uploaded on 05/03/2013 for the course MATH Algebra taught by Professor Wong during the Fall '13 term at Chicago Academy High School.

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