Stitz-Zeager_College_Algebra_e-book

Since we are solving 2x2 x 3 0 we look for solutions

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Unformatted text preview: ative so the height functions becomes s(t) = −4.9t2 − 15t + 25. 6. 495 cookies 7. Make the vertex of the parabola (0, 10) so that the point on the top of the left-hand tower where the cable connects is (−200, 100) and the point on the top of the right-hand tower is 9 (200, 100). Then the parabola is given by p(x) = 4000 x2 + 10. Standing 50 feet to the right of the left-hand tower means you’re standing at x = −150 and p(−150) = 60.625. So the cable is 60.625 feet above the bridge deck there. 8. The largest rectangle has area 12.25in2 . 8 You’ll need to use your calculator to zoom in far enough to see that the vertex is not the y -intercept. 2.3 Quadratic Functions √ 9. (a) x = ±y 10 (b) x = ±(y − 2) √ m ± m2 + 4 (c) x = 2 153 (d) t = (e) y = v0 ± 3± √ (f) y = 2 ± x 2 v0 + 4gs0 2g 16x + 9 2 154 2.4 Linear and Quadratic Functions Inequalities In this section, not only do we develop techniques for solving various classes of inequalities analytically, we also look at them graphically....
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This note was uploaded on 05/03/2013 for the course MATH Algebra taught by Professor Wong during the Fall '13 term at Chicago Academy High School.

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