{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

Stitz-Zeager_College_Algebra_e-book

# Solving x3 2 3 4 x horizontal scale by a factor of 1

This preview shows page 1. Sign up to view the full content.

This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: the graph of f , then f (a) = b so that g (a) = 2f (a) = 2b puts (a, 2b) on the graph of g . In other words, to obtain the graph of g , we multiply all of the y -coordinates of the points on the graph of f by 2. Multiplying all of the y -coordinates of all of the points on the graph of f by 2 causes what is known as a ‘vertical scaling7 by a factor of 2’, and the results are 7 Also called a ‘vertical stretch’, ‘vertical expansion’ or ‘vertical dilation’ by a factor of 2. 94 Relations and Functions given below. y y (5, 10) 10 10 9 9 8 8 7 7 6 6 (2, 6) (4, 6) (5, 5) 5 5 4 4 (2, 3) 3 3 (4, 3) 2 (0, 2) (0, 1) 1 1 2 3 4 5 x 1 vertical scaling by a factor of 2 2 3 4 x 5 −− − − − − − − − −→ −−−−−−−−−− y = f (x) y = 2f (x) multiply each y -coordinate by 2 If we wish to graph y = 1 f (x), we multiply the all of the y -coordinates of the points on the graph 2 1 1 of f by 2 . This creates a ‘vertical scaling8 by a factor of 2 ’ as seen below. y y (5, 5) 5 5...
View Full Document

{[ snackBarMessage ]}

Ask a homework question - tutors are online