The amplitude measures the maximum displacement of

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Unformatted text preview: − π ∪ − π , π ∪ π , π . Returning to arctan(2t), we note the double angle 2 4 44 42 2 identity tan(2t) = 1−tan(t()t) , is valid for values of t under consideration, hence we get tan2 2 2 tan(2 arctan(x)) = tan(2t) = 1−tan(t()t) = 1−x 2 . To find where this equivalence is valid we x tan2 first note that the domain of arctan(x) is all real numbers, so the only exclusions come from the x values which correspond to t = ± π , the values where tan(2t) is undefined. 4 2 Since x = tan(t), we exclude x = tan ± π = ±1. Hence, tan(2 arctan(x)) = 1−x 2 4 x 5 for (−∞, −1) ∪ (−1, 1) ∪ (1, ∞). holds (b) We let t = arccot(2x) so that 0 < t < π and cot(t) = 2x. In terms of t, cos(arccot(2x)) = cos(t), and our goal is to express the latter in terms of x. Since cos(t) is always defined, there are no additional restrictions on t, and we can begin using identities to get exprest) sions for cos(t) and cot(t). The identity cot(t) = cos(t) is valid for t in (0, π ), so if...
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This note was uploaded on 05/03/2013 for the course MATH Algebra taught by Professor Wong during the Fall '13 term at Chicago Academy High School.

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