The factors of 3 are 1 and 3 since the rational zeros

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Unformatted text preview: ormed at the beginning of the section and try to streamline it. First off, let’s change all of the subtractions into additions by distributing through the −1s. x2 + 6 x + 7 x−2 x3 + 4x2 − 5x −14 −x3 + 2x2 6x2 − 5x −6x2 + 12x 7x −14 −7x+14 0 Next, observe that the terms −x3 , −6x2 , and −7x are the exact opposite of the terms above them. The algorithm we use ensures this is always the case, so we can omit them without losing any 3 4 Yes, Virginia, there are algebra courses more abstract than this one. Jeff hates this expression and Carl included it just to annoy him. 3.2 The Factor Theorem and The Remainder Theorem 199 information. Also note that the terms we ‘bring down’ (namely the −5x and −14) aren’t really necessary to recopy, and so we omit them, too. x2 + 6 x + 7 x−2 x3 +4x2 − 5x −14 2x2 6x2 12x 7x 14 0 Now, let’s move things up a bit and, for reasons which will become clear in a moment, copy the x3 into the last row. x2 + 6 x + 7 x−2 x3 +4x2 − 5x −14 2x2 12x 14 x3...
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This note was uploaded on 05/03/2013 for the course MATH Algebra taught by Professor Wong during the Fall '13 term at Chicago Academy High School.

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