{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}


The vertex is the point on the parabola closest to

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: .5.3. Iodine-131 is a commonly used radioactive isotope used to help detect how well the thyroid is functioning. Suppose the decay of Iodine-131 follows the model given in Equation 6.5, and that the half-life10 of Iodine-131 is approximately 8 days. If 5 grams of Iodine-131 is present initially, find a function which gives the amount of Iodine-131, A, in grams, t days later. Solution. Since we start with 5 grams initially, Equation 6.5 gives A(t) = 5ekt . Since the half-life is 8 days, it takes 8 days for half of the Iodine-131 to decay, leaving half of it behind. Hence, A(8) = 2.5 which means 5e8k = 2.5. Solving, we get k = 1 ln 1 = − ln(2) ≈ −0.08664, which we can interpret 8 2 8 as a loss of material at a rate of 8.664% daily. Hence, A(t) = 5e− t ln(2) 8 ≈ 5e−0.08664t . We now turn our attention to some more mathematically sophisticated models. One such model is Newton’s Law of Cooling, which we first encountered in Example 6.1.2 of Section 6.1. In that example we had a cup of coffee cooling from 160◦ F to room temperature 70◦ F according to the formula T (t) = 70 + 90e−0.1t , where t was measured in minutes. In...
View Full Document

{[ snackBarMessage ]}

Ask a homework question - tutors are online