{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

Stitz-Zeager_College_Algebra_e-book

This means 5 that is a quadrant ii angle which we can

This preview shows page 1. Sign up to view the full content.

This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: revious problem. Let t = arccsc(−5) and let 2 π θ = t radians. Then csc(θ) = −5 which means π ≤ θ < 32 . Let α be the reference angle for θ. π Then 0 < α < 2 and csc(α) = 5. Hence, α = arccsc(5) = arcsin 1 radians, where the last 5 equality comes from Theorem 10.29. Since, in this case, θ = π + α = π + arcsin 1 ≈ 3.3430 5 radians, we get arccsc(−5) ≈ 3.3430. y 1 θ α 1 x The inverse trigonometric functions are typically found in applications whenever the measure of an angle is required. One such scenario is presented in the following example. Example 10.6.6. 6 The roof on the house below has a ‘6/12 pitch.’ This means that when viewed from the side, the roof line has a rise of 6 feet over a run of 12 feet. Find the angle of inclination 6 The authors would like to thank Dan Stitz for this problem and associated graphics. 716 Foundations of Trigonometry from the bottom of the roof to the top of the roof. Express your answer in decimal degrees, rounded to the nearest hundredth of a degree. Front View Side View Solution. If...
View Full Document

{[ snackBarMessage ]}

Ask a homework question - tutors are online