Stitz-Zeager_College_Algebra_e-book

To do this we take the ratio of their 6 frequencies

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: ce, all solutions here are 1 of the form θ = π − α + 2πk = π − arcsin 3 + 2πk , for integers k . 2. Even though we are told t represents a real number, it we can visualize this problem in terms of angles on the Unit Circle, so at least mentally,11 we cosmetically change the equation to √ We could solve x2 = 4 using square roots as well to get x = ± 4, but, we would simplify the answers to x = ±2. 11 In practice, this is done mentally, or in a classroom setting, verbally. Carl’s penchant for pedantry wins out here. 10 718 Foundations of Trigonometry tan(θ) = −2. Tangent is negative in two places: in Quadrant II and Quadrant IV. If we proceed as above using a reference angle approach, then the reference angle α must satisfy 0 < α < π and tan(α) = 2. Such an angle is α = arctan(2) radians. A Quadrant II 2 angle with reference angle α is π − α. Hence, the Quadrant II solutions to the equation are θ = π − α + 2πk = π − arctan(2) + 2πk for integers k . A Quadrant IV angle with reference angle α is 2π...
View Full Document

This note was uploaded on 05/03/2013 for the course MATH Algebra taught by Professor Wong during the Fall '13 term at Chicago Academy High School.

Ask a homework question - tutors are online