Stitz-Zeager_College_Algebra_e-book

To do this we take the ratio of their 6 frequencies

Info icon This preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: ce, all solutions here are 1 of the form θ = π − α + 2πk = π − arcsin 3 + 2πk , for integers k . 2. Even though we are told t represents a real number, it we can visualize this problem in terms of angles on the Unit Circle, so at least mentally,11 we cosmetically change the equation to √ We could solve x2 = 4 using square roots as well to get x = ± 4, but, we would simplify the answers to x = ±2. 11 In practice, this is done mentally, or in a classroom setting, verbally. Carl’s penchant for pedantry wins out here. 10 718 Foundations of Trigonometry tan(θ) = −2. Tangent is negative in two places: in Quadrant II and Quadrant IV. If we proceed as above using a reference angle approach, then the reference angle α must satisfy 0 < α < π and tan(α) = 2. Such an angle is α = arctan(2) radians. A Quadrant II 2 angle with reference angle α is π − α. Hence, the Quadrant II solutions to the equation are θ = π − α + 2πk = π − arctan(2) + 2πk for integers k . A Quadrant IV angle with reference angle α is 2π...
View Full Document

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern